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The entropy of system 2 is twice as high as that of system 1. The entropy of sys

ID: 1578196 • Letter: T

Question

The entropy of system 2 is twice as high as that of system 1.

The entropy of system 2 is a lot more than twice as high compared to system 1.

The number of microstates of system 2 is twice as high as those of system 1.

The number of microstates of system 2 is a lot more than twice as high as those of system 1.

You cant tell anything about the comparative entropy of the two systems without more information.

S1 and S2 decrease by equal amounts.

S1 and S2 decrease by unequal amounts.    

S1 increases, but S2 decreases by more.

S1 increases and S2 decreases, but S1 increases by more.

S2 increases, but S1 decreases by more.

S2 increases and S1 decreases, but S2 increases by more.

S1 increases and S2 decreases by equal amounts.



S =  J/K.

1. Suppose we have two identical boxes of matter, A and B, that are in thermal contact but cannot exchange materials. They come to thermal equilibrium. System 1 consists of box A alone, while system 2 consists of both boxes A and B. What can you say about the entropy of the two systems? Choose all correct answers.

The entropy of system 2 is twice as high as that of system 1.

The entropy of system 2 is a lot more than twice as high compared to system 1.

The number of microstates of system 2 is twice as high as those of system 1.

The number of microstates of system 2 is a lot more than twice as high as those of system 1.

You cant tell anything about the comparative entropy of the two systems without more information.

System 1 System 2 A B

Explanation / Answer

1)

The entropy of system 2 is twice as high as that of system 1.
The number of microstates of system 2 is a lot more than twice as high as those of system 1.
2)

S1 increases and S2 decreases, but S1 increases by more

3)   S= Q/T
Q=(1/TC-1/TH)
(0.5J)(1/250K-1/350K)
=.00571 J/K

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