23.104 -RLC Series AC Circuits n RLC series circuit has a 1.00 k resistor, a 120
ID: 1577581 • Letter: 2
Question
23.104 -RLC Series AC Circuits n RLC series circuit has a 1.00 k resistor, a 120 mrl inductor, and a 27.0 F capacitor. Find the power factor at-8.10 Hz. Submit Answer Incorrect. Tries 2/10 Previous Tries What is the phase angle at this frequency? Submit Answer Tries 0/10 If the voltage source has Vrms 360 V, what is the average power at this frequency? Submit Answer Tries o/10 Find the average power at the circuit's resonant frequency Submit Answer Tries 0/10 10 © 1998-2018 by Florida State University. All rights reserved The contents of this web site are for use by the students enrolled in this course only. Any distribution of the contents in whole or in parts and in any form, including posting on the web or in printed versExplanation / Answer
R = 1000 ohm
XL = 2 pi f L = 2 x pi x 8.10 x 0.120
XL = 6.11 ohm
Xc = 1 / (2 pi f C) = 727.7 ohm
Power factor = R / Z
and Z = sqrt[ R^2 + (XL - XC)^2]
so Power factor = 0.81 .....Ans
power factor = cos(theta)
theta = 35.8 deg ......Ans
Pavg = (Vrms^2 / Z ) P.F.
= 85.2 Watt .....Ans
at resonant frequency, PF = 1 and Z = R = 1000 ohm
P = 129.6 Watt ...Ans
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