Homework Questions Vie HOMEWORK PRACTICE SHEET PHY1025 | CLASS: 010751 | Prof. F
ID: 1577504 • Letter: H
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Homework Questions Vie HOMEWORK PRACTICE SHEET PHY1025 | CLASS: 010751 | Prof. Franklin VanSplunteren LECTURE3 MOTION IN 2 OR 3 DIMENSIONS PROBLEM 1 HINT-start by reviewing 3.1 Posision and Velocity Vectors An object has x and y coordinates (1.1m, 3.4m) at time t-Os and has coordinates (5.3m, -0.5m) at time t=3s. Find the x and y components of the average velocity. (1): 14m/s, -13m/s (2): 1.4m/s, -1.3m/s (3): None of the above PROBLEM 2 HINT-start by reviewing 3.3 Projectile Motion A rock is dropped from a cliff and reaches the ground in 2.70s. At the same time another rock is thrown horizontally from the same height with initial x velocity of 0.95 m/s. What distance will in x will the second rock cover? (1): 12.47m (2): 3.57 m (3): 2.57 m PROBLEM 3 HINT-start by reviewing 3.3 Projectile Motion t 0480 s ,--9.30 m/s, +4 t 0480 s A book slides off a table with a horizontal speed of 1.10m/s and strikes the floor at t-0.480s. Find the height of the tabletop, and the magnitude and direction of vector v just before it hits the floor (see above) (1): Height- 1.13m above the floor, vector v magnitude 4.83m/s. Angle alpha-66.8 degrees below horizontal. (2): Height- 1.13m above the floor, vector v magnitude-0.483m/s. Angle alpha-66.8 degrees below horizontal. (3): None of the above Page 1 of 4Explanation / Answer
1. average velocity = displacement / time
v_x = (5.3 - 1.1)/(3- 0) = 1.4 m/s
v_y = (-0.5 - 3.4) / 3 = -1.3 m/s
Ans: (2) 1.4 , - 1.3
2. second rock will also travel for 2.70 s.
x = 0.95 x 2.70 = 2.57 m
Ans(3)
3. in vertical,
yf - yi = v0y t + ay t^2 / 2
0 - h = 0 - 9.8(0.480^2)/2
h = 1.13 m
vx = 1.10 m/s
vy = 0 - (9.8 x 0.480) = - 4.7 m/s
v = sqrt(vx^2 + vy^2) = 4.83 m/s
direction = tan^-1(-4.7/1.10) = 76.8 deg below
angle given is 66.8 deg
henc (3) None of the above
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