a box of can goods slides down a ramp from street level into the basement of a g

Question

a box of can goods slides down a ramp from street level into the basement of a grocery store with an acceleration of 0.75 m/s2 directed down the ramp. The ramp makes an angle or 40 degrees with the horizontal. What is the coefficient of friction between the box and the ramp? a box of can goods slides down a ramp from street level into the basement of a grocery store with an acceleration of 0.75 m/s2 directed down the ramp. The ramp makes an angle or 40 degrees with the horizontal. What is the coefficient of friction between the box and the ramp?

Explanation / Answer

Here ,

acceleration ,a = 0.75 m/s^2

theta = 40 degree

let the coefficient of friction is u

for the acceleration

m * a = m * g * sin(theta) - u * m * g * cos(theta)

a = 9.8 * (sin(theta) - u * cos(theta))

0.75 = 9.8 * (sin(40 degree) - u * cos(40 degree))

solving for u

u = 0.74

the coefficient of friction is 0.74

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