//usq45tut Study I New tab Homework: 2-D Motion Begin Date: 1/31/2018 12.00:00 A
ID: 1577192 • Letter: #
Question
//usq45tut Study I New tab Homework: 2-D Motion Begin Date: 1/31/2018 12.00:00 AM-Due Date: 2/7/2018 11.5900 PMEnd Date: 2/14/2018 1159 00 PM (11%) Problem 9: A high school physics instructor catches one of his students chewing student by asking that he stick the gum to a fan and calculate how fast the fan is moving when the gum gets thrown off The label says that the diameter of the fan is d-39 cm, and at full speed it turns at a rate of f 55 revis, and that the fan is guaranteed to accelerate uniformly. The fan takes 11 s to go from rest to full speed Randomized Variables d=39 cm 14% Part (a) Calculate the maximum the angular velocity of the fan aan. in radians per second Grade Summary Poettal 100% cotanO asinacos0 atan acotan0 sin0 leted Attempts reaaining 20 uare second, as the fan is speeding up radians per sq ·14-, Part (c) Calculate the tangential component of the acceleration of the gum a n meters per square second, as the fans speeding up what is the magnitude of the centripetal acceleration of the gum at in meters per square second, when the fan reaches full 14% Part (d) 14% Part (e) What is the d rection of the centripetal acceleration ofthe gun, as the fans turning at topspeed? 14% Part (f) Calculate the tangential component of the acceleration of the gus ags, in mesers per square secoed, when the fan is at ful frons the fan blade Detemmine the linear speed of the gum v, inExplanation / Answer
(a) w = 55*2 = 345.58 rad/s
(b) alpha = w/t = 345.58/11 = 31.42 rad/s2
(c) Final tangential speed of fan blade tip = V = wR = (55(2)rad/s)(0.39/2 m) = 67.39 m/s
Tangential acceleration = (V-0)/t = 67.39/11 = 1.55 m/s²
(d) Ac = V²/R = (67.39)²/(0.39/2) = 23289 m/s²
(e) Centripetal = means "center seeking" ie Ac is at all times directed toward the center of rotation.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.