The lines show the equipotential contours in the plane of three point charges, Q

Question

The lines show the equipotential contours in the plane of three point charges, Q1, Q2, and Q3. The values of the potentials are in kV as indicated for the +5, 0, and 5 kV contours, The positions of the charges are indicated by the dots. Q1 Q2 olts Q3 cm1 2 3 4 5 The letters are on the equipotential contours Calculate the size of the force on a charge of 4.80x10-19 C at k. 9.60 10-14)N First calculate the electric field in the same way as you did for the previous problem. Then, remember the relation between force and E-field. Submit Answer Incorrect. Tries 4/12 Previous_Tries

Explanation / Answer

Electric field is always perpendicular to equipotential contours.

& electric field is calculated as gradient of electric potential.

At k the electric potential is zero. Potential contour next to it is f which is of -1 kV. The approximate pependicular distance between k and f is 0.5 cm (According to the scale provided).

Hence magnitudeelectric field at k

E = V/r

=1000/0.005

E = 200000 N/C

Force on charge q = 4.8 x 10-19 C

F = qE

= 4.8 x 10-19 C x 200000 N/C

F = 9.6 x 10-14 N towards contour f

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