A negative charge and a positiye charge with the same magnitude of charge, q are

Question

A negative charge and a positiye charge with the same magnitude of charge, q are fixed on an x- axis at ± d, as illustrated. ty Rttrached +i,b brcause s and 0, C +x The net force exerted by these charges on a negative charge on the ty-axis will be directed in: a. the +x-direction b, the-x-direction c.the +y-direction d. the -y-direction Part B (8.5 pts) Three charges, qi +16.0x10* C, q2--8.0x10 C, and q-+8.0x10 C are fixed at x,--7.5 cm, y2 = +7.5 cm, and x,-+7.5 cm, respectively, as in the diagram. A charge, q--8.0x10* C is placed at the origin. Determine the magnitude of the total force on qa due to the other 3 charges. (Make sure the steps in your solution are clear.) 43 7Son

Explanation / Answer

|F14| = k*q1*q4/d^2

= 9*10^9*16*10^-8*8*10^-8/0.075^2

= 0.0205 N (towards -x axis)

|F24| = k*q2*q4/d^2

= 9*10^9*8*10^-8*8*10^-8/0.075^2

= 0.0102 N (towards -y axis)

|F34| = k*q3*q4/d^2

= 9*10^9*8*10^-8*8*10^-8/0.075^2

= 0.0102 N (towards +x axis)

Fnetx = |F34| - |F14|

= 0.0102 - 0.0205

= -0.0102 N

Fnety = -0.0102 N

Fnet = sqrt(Fnetx^2 + Fnety^2)

= sqrt(0.0102^2 + 0.0102^2)

= 0.0144 N <<<<<<------------------------Answer

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