f= | Value ll Units Constants I Periodic Table A 140 g block hangs from a spring
ID: 1575327 • Letter: F
Question
f= | Value ll Units Constants I Periodic Table A 140 g block hangs from a spring with spring constant 9.0 N/m Att = 0 s the block is 31 cm below the equilibrium point a moving upward with a speed of 101 cm/s and Part B What is the block's distance from equilibrium when the speed is 69 cm/s ? Express your answer to two significant figures and include the appropriate units. Zi= 1 Value ll Units Submit Part C What is the block's distance from equilibrium at 5.0s? Express your answer to two significant figures and include the appropriate units.Explanation / Answer
f = sqrt(k/m) / 2pi
f = sqrt(9 / 0.140) / 2pi
f = 1.276 Hz
(B) total energy = k x^2 /2 + m v^2 /2 = constant
9 (0.31^2) + 0.140(1.01^2) = 9 x1^2 + 0.140 (0.69^2)
0.8649 + 0.1428 = 9 x1^2 + 0.06665
x1 = 0.323 m Or 32.3 cm
(C) w = 2 pi f = 8.02 rad/s
1.01^2 = (8.02^2) (A^2 - 0.31^2)
A = 0.335 m = 33.5 cm
x = - A cos(wt + phi)
31= - 33.5 cos(0 + phi)
phi = 0.389 rad
(D) x = -33.5 cos((8.02 x 5) + 0.389)
x = 31.4 cm
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