No Service 10:22 AM * 35% webassign.net REMARKS To find the rest of the charges

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No Service 10:22 AM * 35% webassign.net REMARKS To find the rest of the charges and voltage drops, it's just a matter of using C = Q/ar. repeatedly, together with facts 5C and SE in the Problem-Solving Strategy. The voltage drop across the 4.0-uF capacitor could also have been found by noticing, in figure b, that both capacitors had the same value and so by symmetry would split the total drop of 12 volts between them. QUESTION Which capacitor holds more charge, the 1.0-uF capacitor or the 3.0-HF capacitor? O The 1.0-uF capacitor. O The 3.0-HF capacitor. O They both have the same charge EXERCISE HINTS: GETTING STARTED IM STUCK! (a) Find the charge on the 8.0-HF capacitor in Figure (a) and the voltage drop across it. HC Is the entire battery voltage placed across this single capacitor? V (b) Do the same for the 6.0-uF capacitor in Figure (a). This circuit has both series and parallel combinations of capacitors rather than being a simple series Would you expect each capacitor to have the same charge as the equivalent capacitor? Why or why not? HC Need Help?Read lit

Explanation / Answer

a)
The 6.0 µF capacitor in parallel with the 2.0 µF capacitor form a 8.0 µF capacitor. It is in series with another 8.0 µF capacitor; with two equal capacitors in series, half of the applied voltage appears across each one.
If that applied voltage is 12 V, then 6 V is across the 8.0 µF capacitor, and the charge Q =V*C
= 6*8.0
=> Q = 48 µC
V = 6 V

b)
The 6.0 µF capacitor also has 6 V across it, so its charge is Q = 6.0*6.0
= 36 µC
V = 6 V

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