two point charges are placed on the x axis. the first charge Q1=8n/c i\'s placed

Question

two point charges are placed on the x axis. the first charge Q1=8n/c i's placed a distance x1=13m from the origin along the positive x axis;the second charge Q2 2.5nC is places q distance x2=7.0m from the origin along the negative x axis. now assume charge q2 is negative q2=-2.5 nd as shown what is the net electric field origin point O?

Web 2.0 s 4 of 7 Los Part B Now, assume that charge Q2 is negative: Q2 =-2.5 nC as shown in (Figure 2). What is the net electric field at the origin, point O? Give the x and y components of the electric field as an ordered pair. Express your answer in newtons per coulomb to three significant figures. Keep in mind that an x component that points to the right is positive and a y component that points upward is positive. View Available Hint(s) Hint 1. What changes I 01 and @2 have the same magnitude of charge as before and they are the same distance from the origin as before, so do the electric field magnitudes Eo and E02 change? Yes Previous Answers Correct Hint 2. What changes I Do the directions of the electric fields at 0 change? (Both the original and new problems are shown for comparison.) ntent and ads We also share

Explanation / Answer

electric field due to Q1, E1 = kQ1/(132) = 9*109*8*10-9/(132) = 0.426 N/C towards negative x axis

electric field due to Q2, E2 = kQ2/(72) = 9*109*2.5*10-9/(72) = 0.4591 N/C towards negative x axis

net field at origin, E=E1 + E2 = 0.8851 N/C

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