1. At 2330 UTC on October 29, 2012, \"Superstorm\" Sandy made landfall near Atla

Question

1. At 2330 UTC on October 29, 2012, "Superstorm" Sandy made landfall near Atlantic City, New Jersey, with a central pressure of 945 hPa. In Philadelphia, Pennsylvania, 92 km to the northwest, the pressure was 963 hPa. To get away from the storm surge, a group of friends drove to Vineland (west-northwest of Atlantic City) at a speed of 38 m/s. An onboard Kestrel instrument measured pressure increasing at a rate of How did the pressure change over the next 2.25 hours in Vineland? 0.006 hPa/s. 0 Township Philadelphia on Vineland Atlantic City Dover

Explanation / Answer

let rat eof change of pressure in the superstorm wrt radius lambda
let speed of the superstorm be u in arbitrary direction

now, from the given equations
let distance covered by the people be x
then
dx/dt = 38 m/s
also

at distance x form the center of the storm
lambda(r) = 0.006 h Pa/s = dP/dt

hence
0.006 = dP/dx * dx/dt = dP/dx * 38
hence
dP = 1.57894*dx
P = 1.57894x + k

hence for Vineland
dP/dt = 1.57894*38 = 0.006 h Pa

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