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ID: 1574663 • Letter: S
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sonal St e How to Seek God Wi a Anatomy of the Brain P Pandora Internet RadRather Be Performing A Employee-facing reg Home Student: brandyce.roberts@mavs.uta.e Class l Help Homework 1 Begin Date: 1/18/2018 2:00:00 PM - - Due Date: 1/30/2018 11:59:00 PM End Date: 1/31/2018 3:00:00 AM (796) Problem 10: An electron has an initial velocity of 5.1 × 106 m s in a uniform 1.9 x 105 N C electric field. The field accelerates the electron in the direction opposite to its initial velocity. 25% Part (a) what is the direction of the electric field? 25% Part (b) How far does the electron travel before coming to rest in m? Grade Summarv Potential Submissions 80% cos0 cotan0 asin acosO atan acotan sinh cosh0anh0cotanh0 O Degrees O Radians sin0 Attempts remaining: S % per attempt) detailed view 50% 50% 50% 50% Submit Hint I give up! Hints:--deduction per hint. Hints remaining: 3 Feedback: 2% deduction per feedback. 25% Part (c) How long does it take the electron to come to rest in s? 25% Part (d) What is the magnitude of the electron's velocity (in m s) when it returns to its starting point in the opposite direction of its initial velocity?Explanation / Answer
(b) a = F/m
= q*E / m
= 1.602e-19C * 1.9e5N/C / 9.11e-31kg
= 3.34e16 m/s²
Then d = v² / 2a = (5.1e6m/s)² / (2*3.34e16m/s²)
= 3.89 x 10^-4 m
(c) t = v / a
= (5.1e6)/ (3.34e16)
= 1.53 x 10^-10 s
(d) 5.1e6 m/s
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