5. Two small steel ball bearings have the same radius and they are located 1.2 m

Question

5. Two small steel ball bearings have the same radius and they are located 1.2 m apart. One has a charge of +3 0, while the other has a charge of-5 C, what is the electric force they exert on each other? (94 mN, attractive 6. The steel balls from question #5 are brought in contact with each other, and then replaced in their original positions. What charge does each ball have now? (Each ball has-1 HC of charge.) 7. Now, what is the electric force the ball bearings exert on cach other? (6.3 mN, repulsive)

Explanation / Answer

5) F = KQ1Q2/R^2

F = 9*10^9*3*5*10^-12/1.2^2 = 93.75 *10^-3 = 94 mN

here charges has oposite sign so theny are attractive in nature

6) total charge is q1+q2 = 3-5 = -2 *10^-6 C

each ball acquires the charge of -1*10^-6 C

7) f = 9*10^9*1*10^-12/1.2^2 = 6.25mN now both are having negative charge so they are repulsive in nature.

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