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Bookmarks Develop Window Help 60 saplinglearning.com Apple iCloud Yahoo Bing Google Wikipedia Google Yahoo University of California, Merced-PHYS 18 -Spring18 -LIU: HW: Motion Along a Straight Line Jump to... PrintCalculatorPeriodic Table ion 14 of 17 Sapling Learning Map o. The position x, in meters, of an object moving along the x-axis is given as a function of time t, in seconds, as x (r)-0.08851-0-265rs + 0.79 + 3.09t-8.01 Find the object's acceleration at time t = 3.41 s. Number m/ s Provos Give up & View Sonor, 9Check Answer ONet tl Exit

Explanation / Answer

x(t) = 0.0885t^4 - 0.265t^3 + 0.797t^2 + 3.09t - 8.01

dx(t)/dt = v(t) = 4*0.0885t^3 - 3*0.265*t^2 + 2*0.797t + 3.09

dv(t)/dt = a(t) = 3*4*0.0885t^2 - 2*3*0.265t + 2*0.797

a(3.41) = (3*4*0.0885*(3.41)^2) - (2*3*0.265*3.41) + (2*0.797)

= 8.52 m/s^2

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