..1 T-Mobile Wi-Fi 7:24 PM webassign.net 86%- We know the potential difference b
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..1 T-Mobile Wi-Fi 7:24 PM webassign.net 86%- We know the potential difference between the plates and the distance d 5.06 mm between the plates. Therefore, the magnitude of the electric field between the plates is E..an x 105 v/m × 10-3m 105 N/C Need Help? H My Notes Ask Your Tea An electron is at the origin. (a) Calculate the electric potential VA at point A, x-0.395 cm. (b) Calculate the electric potential V, at point B, x = 0.545 cm. What is the potential difference VB VA? (c) Would a negatively charged particle placed at point A necessarily go through this same potential difference upon reaching point B? Explairn This answer has not been graded yet Need Help? Red The two charges in the figure below are separated by d = 4.00 cm. aet 41 .-19.5 nC and q2·26.5 nC)Explanation / Answer
a) Electric potential at point a :-
Va = ( ke*q / x )
Va = ((9*10^9 * 1.6*10^-19) / 0.00395)
Va = 3.6455*10^-7 V
b) Electric potential at point b :-
Vb = ( ke*q / x )
Vb = ((9*10^9 * 1.6*10^-19) / 0.00545)
Vb = 2.642*10^-7 V
Delta V = Vb - Va
= (2.642*10^-7)-(3.6455*10^-7)
= -1.0035*10^-7 V
c). it will not going, because Vb > Va
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