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27. Two charges are located on the positive x-axis of a coordinate system. Charg

ID: 1573804 • Letter: 2

Question

27. Two charges are located on the positive x-axis of a coordinate system. Charge 2*10C is 2cm from the origin, and charge q3*10 C is 4cm from the origin (the electrical constant k ~ 9 * 10, Mm2C-2 ). What is the total force exerted by these two charges on a charge q, = 5 * 10 located at the origin? (a) -2.25 * 10-N (b)-1.41*10-N (c) 0.84 10 N (d) 1.68#10"W 28. Two positive point charges, each of magnitude q, are fixed on the y-axis at the points y a and y-a Suppose a positively charged particle of charge q' and mass m is placed precisely at the origin and is displaced slightly in the direction of the y-axis, what will happen? (a) It remains at rest (b) It oscillates about the origin, along the x-axis (c) It accelerates away from the origin along the x-axis (d) It moves along the x-axis with constant velocity 29. A particle having a mass of 0.5g carries a charge of 2.5 10C. The particle is given an initial horizontal velocity of 6*10mis. What is the magnitude and direction of the minimum magnetic field that will keep the particle moving in a horizontal direction? (a) 2.37T, perpendicular to direction of v (b) 2.37T, parallel to direction of v (c) 3.27T, perpendicular to direction of v (d) 3.27T, parallel to direction of v .

Explanation / Answer

F31 =kq1q3/d^2=9×10^9×2×10^-9×5×10^-9/0.02^2

=225×10^-6N direction of force will be to the left

F32 =9×10^9×5×10^-9×3×10^-9/0.04^2

=84.38×10^-6N direction of force will be to the right

So net force wil be 140.63×10^-6N direction wil be to the left

Can be written as -1.41×10^-4N

28)it oscillates about the origin along the + x axis because of equal and opposite forces

29)mg=Bqvsin90

0.5×10^-3×9.8=B×2.5×10^-8×6×10^-4

B=0.5 ×10^-3×9.8/2.5×10^-8×6×10^-4

B=3.27×10^8T perpendicular to direction of v

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