Protons are projected with an initial speed v, 9.34 km\'s froma field-free regio

Question

Protons are projected with an initial speed v, 9.34 km's froma field-free region through a plane and into region where a uniform electric field E =-720j NC is present above the plane as shown in in the figure below. The initial velocity vector of the protons makes an angle with the plane. The protons are to hit a target that lies at a horizontal distance of R = 1.19 mm fro the point where the protons ooss the plane and enter the electric feld, we wish to find the angle at which the protons must pass through the plane to strike the target. Proton beam E- bekow the plane (c) Argue that R ask you to turn in this work.) would be applicable to the protons in this situation. (Do this on paper. Your instructor may to write an expression for R in terms of v, E, the charge and mass of the proton, and the angle . (Use the following as necessary: v, e, E, , and m, for the mass of proton.) e) Find the two possible values of the angle . (Enter your anavvers from smallest to largest.) Fnd the time interval during which the proton is above the plane in the figure above for each of the two possible values Enter your answers from smallest to largest.) Your response differs significantly from the correct anewer Rework your solution from the beginning and check each sep Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully, ns

Explanation / Answer

f) smallest time taken,

t = R/vix

= R/(vi*cos(34.83))

= 1.19*10^-3/(9.24*10^3*cos(34.83))

= 1.57*10^-7 s

= 157 ns

Largest time taken,

t = R/vix

= R/(vi*cos(55.14))

= 1.19*10^-3/(9.24*10^3*cos(55.14))

= 2.25*10^-7 s

= 225 ns

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.