I need help answering this question using Microsoft Excel. I would tremendous ap
ID: 1573229 • Letter: I
Question
I need help answering this question using Microsoft Excel. I would tremendous appreciate the work shown in order to identify the steps and understand the concept more in-depth.
45 Force Components and Tension in Wires I A 150-kg mass is suspended by wires from two hooks, as shown in the accom figure. The lengths of the wires have been adjusted so that the wires are each from horizontal, as illustrated in Figure 4.57. Assume that the mass of the vw negligible panyin Figure 4.57 Forces and tensions irn wires, I 50e fh 150 kg a. Two hooks support the mass equally, so the vertical component of force exerted by either hook will be equal to the force resulting from 75 kg being acted on by gravity. Calculate this vertical component of force, on the right hook. Express your result in newtons. b. Compute the horizontal component of force,, by using the result c. Determine the force exerted on the mass in the direction of the wire d. If you moved the hooks farther apart to reduce the angle from 50 to 30 obtained in part (a) and trigonometry (equal to the tension in the wire), would the tension in the wires increase or decrease? Why?Explanation / Answer
(a) Using sysmmetricity -
Verical component of each wire = Fy
Horiontal component of each wire = Fx
Now we have -
2*Fy = m*g = 150*9.81 = 1471.5
=> Fy = 1471.5 / 2 = 735.75 N
(b) As shown in the diagram of the resolved forces -
Fy = Fr*sin50
=> Fr = Fy / sin50 = 735.75 / sin50 = 960.45 N
So, horiontal component of the force, Fx = Fr*cos50 = 960.45*cos50 = 617.37 N
(c) Tension in each wire = Fr = 960.45 N
(d) Angle is reduced from 50 deg to 30.
now, sin50 > sin30
Vertical component Fy of the force is constant and sin30 comes at denominator.
So, the resulting tension in the wire Fr will INCREASE.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.