(10%) Problem 7: A bacterium has 3.5 × 10 16 protons and a net charge of 4.1 pc.

Question

(10%) Problem 7: A bacterium has 3.5 × 10 16 protons and a net charge of 4.1 pc. 50% Part (a) How many fewer electrons are there than protons? Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: 5 cos() sinO cotan0asin0 atan() acotan) cosh) tan() | | ( acos) % per attempt) detailed view 123 0 sinh) tanh cotanh0 END Degrees Radians BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: 1 Feedback: 2% deduction per feedback 50% Part (b) If you paired them up, what fraction of the protons would have no electrons?

Explanation / Answer

Given that,

Np = 3.5*10^16 protons

Net charge, Q = 4.1*10^(-12) C

Let number of electrons n

We know that,

Q = Qp - Qe

4.1*10^(-12) = (3.5*10^16*1.6*10^(-19)) - (n*1.6*10^(-19))

n = 3.5*10^16

So, there is no difference in number of protons and electrons

electrons fewer than protons are 0.

(b)

lf you paired them up, all protons will contain electrons.

so, fraction = Np - Ne / Np = 0 / Np

fraction = 0

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