Question 3 10 pts If the potential due to a point charge is -591V at a distance

Question

Question 3 10 pts If the potential due to a point charge is -591V at a distance of 16.7 m, what are the sign and magnitude of the charge? You need to express the charge in nC. InC 10C You should round your answer to an integer, indicate only the number, do not include the unit. DQuestion 4 10 pts What is the final speed of a free electron accelerated from rest through a potential difference of -62 V? The mass of the electron is 9.11x10kg You need to express the speed in km's. You should round your answer to an integer. indicate only the number, do not include the unit

Explanation / Answer

potential at a point due to point charge V = k*q/r

given v = -591 v

distance r = 16.7 cm = 0.167 m

k = 9*10^9 Nm^2/C^2

charge q = V*r/k = -591*0.167/(9*10^9) = 11 nC

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potential difference V = -62 V

mass of electron m = 9.11*10^-31 kg

q = charge of electron = -1.6*10^-19 C

work done by potential W = V*q

from work energy relation

work = change in kinetic energy

W = (1/2)*m*(vf^2 - vi^2)

vi = initial speed = 0

vf = final speed = ?

-591*-1.6*10^-19 = (1/2)*9.11*10^-31*(vf^2-0)

final speed vf = 14408 km/s

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