You would like to shoot an orange in a tree with your bow and arrow. The orange

Question

You would like to shoot an orange in a tree with your bow and arrow. The orange is hanging 5.00 m above the ground. On your first try, you fire the arrow at 35.0 m/s at an angle of 30.0° above the horizontal from a height of 1.40 m while standing 56.0 m away. Treating the arrow as a point 30.0 5.00 m ectile and neglecting air resistance, what s the height of the arrow once it has 1.40 m traveled the 56.0 m hoizontally to the tree? 56.0m Number If you fire at the same speed and angle on your second try, how far away could you stand such that the arrow will hit the orange? Assume that the orange remains fixed in place during the arrow's flight. Select all that apply. 101m 6.6 m 93m 64.5 m 15.1m

Explanation / Answer

Vx = 35 X cos(30) = 30.31 m/s

Vy = 35 Xsin(30) = 17.5 m/s

the time x = Vx t

56 = 30.31 X t

t = 1.847 sec

s = ut + 1/2 a t2

s = 17.5 X 1.847 - 0.5 X 9.8 X 1.8472

s = 15.6 m

height h = 15.6 + 1.4

h = 17 m

s = u t + 1/2 g t2

1.4 = 17.5 t - 4.9 t2

4.9 t2 - 17.5 t + 1.4 = 0

t = 3.489 sec

or

t = 0.0818 sec

so

s = Vx t = 30.31 X 4.38 = 105.7 m

and

s = Vx t = 30.31 X 0.0818 = 2.47 m

but from above it is 101 m nearest value..

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