7, -13 points YF14 21.P056 The dipole moment of the water molecule (H2o) is 6.11

Question

7, -13 points YF14 21.P056 The dipole moment of the water molecule (H2o) is 6.11030 c m. Consider a water malecule located at the origin whose dipole moment P points in the +x-direction. A chlorine ion (C, of charge 1.60 x 1019 C, is located at x 4.20 10'9 m. Find the magnitude and direction of th e le tric force that the water molecule exerts on the ch ar ne ion. Assume that x is much larger than the separation d between the charges in the d pole, so that the approx mate expression for the electric field along the dipole axis E magnitude My Notes Ask Your can be used, where p is the dipole moment, and y is the distance between ions Is this force attractive ar repulsive? -14 points YF14 21.P.081 My Notes Ask Your A charge 1+4.00 nC is placed at the origin of an xy-coardinate system, and a charge 423.00 nC is placed on the positive x-axis atx-4.00 cm. (a) If a third charge 3 6.00 nC is now placed at the point x-4.00 cm, y 3.00 cm, find the x and y-components of the total force exerted on this charge by the other two (b) Find the magnitude and directian of this force. (counterclockwise fram the x-axis) -12 points YF14 21.P090 My Notes Ask Your gion between them an oil droplet o mass 393 Two very large horizontal snects re 3 5 cm apart and carry equal but opposite uniform surface charge densities o magnitude o. You want o use these sheets o hold stationary in he that carries an excess of five electrons. (a) Assuming that the drop is in vacuum, which way should the electric field between the plates point? upward downward (b) what should be? C/m? Submit Answnr Save Prograss Practice Arathar Varsian

Explanation / Answer

Electric field on axis of dipole

E= k (2*P)/x3= 9*109* 2* 6.17*10-30/(4.2*10-9)3= 1.5*106N/C

F= qE= 2.398* 10-13

Direction, along - x axis

Force is attractive in nature

According to Chegg guidelines we can solve one problem at a time so Plz reattach your other problems seperately

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