Birds have evolved to the ability to control their motions through the air by co
ID: 1572726 • Letter: B
Question
Birds have evolved to the ability to control their motions through the air by controlling the forces exerted on their bodies by the air; the contact forces on a bird by the air plus the force of gravity on the bird by the Earth determine the change in motion of the bird at any instant of time. In this problem, you will be asked to use what you know about acceleration to track the motion of a diving hawk.
A hawk is flying horizontally Southward at an altitude of 132.0 m and at a speed of 2.40 m/s when he spots a slow-flying finch ahead of his current location and below his current path. At time zero, the hawk starts a dive by controlling the contact forces on him by the air so as to produce an acceleration of 5.10 m/s2 in a direction 68.0 degrees below horizontally Southward for a time of 0.750 seconds.
Part C What ia the hawlcs daplacoment during tha 7.5- interval? Glve your answer as an ordered pair, with magnitude first, followed by a comma, then followed by the direction. Glve the direction in terms of an angle measured below the horizontalily Southward direstion magntude, direcion m, degrees below Sout Submit A: tho end of the 7.5-s interval, the hawk missos the finah and has to "put on tho brakos". Ho does so by controling the contact foroes on him by the air so as to produce an acceleration of 4617 in a drecton 63 224 degreeabovo horizontally Northward for a time af 0.7 seconda -Part D What is the haks inal velccity at the end ot the 0,7- interval? Give your anawer as an ordered pair, with magnitude first, followed by a comma, then followed by the direction. Give the direation in terms of an angle measured below the horizontalily Southward direation. Ithe direction is above horizontally South instead of below, use a negative angle Vilew Avalliable Hints magntude. drection mvs, degrees below South Submit Part E Once again, pleaso asoume hat the hak's acceleraion during tho 0.7-s interval is oonstant. What is the hawk's cisplacement during the 0.7-s intorval? Give your answer as an ordered pair, with magnitude first, followed by a comma, then followed by the direction. Give the direction in terms of an angle measured below the horizontaly Southward direction. Vilew Avallable Hints) m, degraes balow South You have now been tracking the rank's motion for a total of 0.750-7.5-0.7·8.95 second8. PartF what is te total Southward displacement of the hawk during thoDe 8.95 Deconda? Specify the drect on with a plus or minus sign aosumng tat Soutward is pootivo and Northward·negativeExplanation / Answer
To obtain the displacement of the hawk during the given period, we use the following relation:
s= ut + 0.5at2, where
s= displacement
u = initial velocity = 2.4 m/s
t = 7.50 s
acceleration, a = 5.10 m/s2
Hence, s = 18+ 143.43 = 161.43m is the required displacement.
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