10. -12 points GPhys05 13.085 MP During an ecology experiment, an aquarium half

Question

10. -12 points GPhys05 13.085 MP During an ecology experiment, an aquarium half filled with water is placed on a scale. The scale shows a weight of 180 N. (a) A rock weighing 9 N is added to the aquarium. If the rock sinks to the bottom of the aquarium, what will the scale read? (b) The rock is removed from the aquarium, and the amount of water is adjusted until the scale again reads 180 N. A fish weighing 2 N is added to the aquarium. What is the scale reading with the fish in the aquarium? Notes Ask Your Tear What is the size of the buoyant force on a 15.0 N ball that is floating in fresh water? 12. 13.087 MP What is the apparent weight of a rock submerged in water if the rock weighs 52 N in air and has a

Explanation / Answer

(10) (a) When the rock weighing 9 N is added in the aquarium, this remains in the aquarium and also the volume of water displaced by this rock also remains in the aquarium.

So, the new reading of the scale = 180 + 9 = 189 N

(b) Due to the same reason as mentioned above, means fish and the displaced volume of water by the fish remains in the aquarium. So, the new reading ofthe scale = 180 + 2 = 182 N

(11) Since the ball floats on the fresh water.

So, the weight of the ball (acts downward) shall be equal to the buoyant force (act in upward direction).

Therefore, the buoyant force = 15.0 N

(12) Take the density of the freash water, rho = 1000 kg/m^3

So, the buoyant force = V*rho*g = 2.4 x 10^-3 x 1000 x 9.81 = 23.54 N

Therefore, the apparant weight of the rock = weight in air - buoyant force

= 52 - 23.54 = 28.46 N

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