If someone could please give a detailed and easy to follow process for answering
ID: 1571989 • Letter: I
Question
If someone could please give a detailed and easy to follow process for answering this question it would be greatly appriciated. Thanks!
BAC AAC (a) Three point charges, A 2.50 HC, B 7.30 uc, and C 3.80 HC, are located at the corners of an equilateral triangle as in the figure above. Find the magnitude and direction of the electric field at the position of the 2.50 HC charge. 60.7 magnitude Your response differs from the correct answer by more than 10%. Double check your calculations, NC dire ° terclockwise from the +x-axis) tionExplanation / Answer
a)
let
d = 0.5 m
EB = k*qB/d^2
= 9*10^9*7.30*10^-6/0.5^2
= 262800 N/c
EBx = -262800*cos(60)
= -262800*10^5*cos(60)
= -131400 N/c
EBy = -EB*sin(60)
= -2.628*10^5*sin(60)
= -226008 N/c
EC = k*qC/d^2
= 9*10^9*3.8*10^-6/0.5^2
= 136800 N/c
ECx = 136800 N/c
ECy = 0
Enetx = EBx + ECx
= -131400 + 136800
= 5400 N/c
Enety = EBy + ECy
= -226072 N/c
Enet = sqrt(Enetx^2 + Enety^2)
= sqrt(5400^2 + 226072^2)
= 226136 N/c <<<<<<<<<<--------------Answer
Direction : theta = tan^-1(Enety/Enetx)
= tan^-1(226136/5400)
= 98.47 degrees <<<<<<<<<<--------------Answer
b) unchanged
c) yes. doubled
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