4.) You have a 30 cm long thin tube open on one end and closed on the other end.

Question

4.) You have a 30 cm long thin tube open on one end and closed on the other end. You blow over the top of the tube and excite the fundamental resonant frequency of the air column in the tube. You measure this fundamental resonant frequency t to be 286 Hz. You now cut the closed end of the tube off (note it is still 30 cm long but now is open at both ends) and blow over it again, exciting the fundamental resonant frequency. Find this new fundamental resonant frequency for the 30 cm long tube open at both ends. Give your answer in Hertz. Hint: Drawing simple diagrams of the standing wave patterns in the tubes may help you solve the problem easily. 7. 5 343 572 H2 343 0.6m

Explanation / Answer

4) fundamental frequency of closed pipe f1 = v/lambda1

= v/[4L]

v = [4*0.30]*286 m/s

fundamental frequency = v/2L = [4*0.30]*286 /[2*0.30]

= 572 Hz

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