1. 2. a 0.200 kg mass of metal with a specific heat of 1255.8 J/(kg C°), initial

Question

1.

2. a 0.200 kg mass of metal with a specific heat of 1255.8 J/(kg C°), initially at 90°C, is placed in 0.500 kg calorimeter, with a specific heat of 418.6 J/(kg C°), initially at 20°C. the calorimeter is filled with 0.100 kg of water initially at 20°C. the specific heat of water is 4186 J/(kg C°). what is the final temperature once the combination of metal, calorimeter, and water reach equilibrium?
a. 70°C
b. 80°C
c. 50°C
d. 40°C

modynamics Graded Exam A particle is moving in simale harmoruc motion accordiag to the equatio TrE) cos3e, where t LE the time in seconds How long does it take the particl to travel directly from lto x- 2? Select one a. 0.365 b- 1.0 s c. 1.7 s d. 3.9 s

Explanation / Answer

mcT = Q. (Let T = final temp.)

Heat lost by the metal = 0.200kg x 1256J/kg/°C x (90 - T) °CT = 22608 - 251T.

Heat gained by the Calorimeter = 0.500kg x 418.6J/kg/°C x (T - 20) °CT

= 209T - 4186

Heat gained by the water = 0.100kg x 4186Jk/g/°C x (T - 20) °CT

= 419T - 8372.

Heat Lost = Heat gained.

22608 - 251T = (209T - 4186) + (419T - 8372).

22608 + 4186 + 8372 = 251T + 209T + 419T.

T = 35166 / 879

T = 40°C

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