ent and Resistance Circuits Chapters 27 & 28 (Current and Resistance, Circuits G

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ent and Resistance Circuits Chapters 27 & 28 (Current and Resistance, Circuits Google Chrome Secure https:// session masteringphysics.com 78074138&offset; next PHYS 192, University Physics II, Spring 2017 Help Clos HW7-Chapters 27 & 28 (Current a Problem 27.28 previous l 3 of 23 l next Problem 27.28 Part A An engineer cuts a 1.0-m-long, 0.33-mm-diameter Find the resistitvity p of the piece of the wire. piece of wire, connects it across a 1.5 V battery, Express your answer with the appropriate units. and finds that the current in the wire is 8.0 A. p Value Units Submit My Answers Give Up Part B This question will be shown after you complete previous question(s) Provide Feedback Continue

Explanation / Answer

R = p(L/A) where p = resistivity of wire, L = length, A = area

V=RI
=R=V/I = 1.5/8.................(1)
R=p(1/ *0.00033*0.00033/4)..(2)

combining (1)and(2)

1.5/8 =p(1/ *0.00033*0.00033)

p= 0.1875/ 11697753.4465
p = 1.602 x 10-8

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