Please provide deep explaining of concepts, theories, and formulas that apply to
ID: 1569826 • Letter: P
Question
Please provide deep explaining of concepts, theories, and formulas that apply to each problem. I have a physics final coming up and I need to be prepared, these are the practice questions. thank you.
o. A 7.0-kg bowling ball strikes 2 kg pin. pin flies forward a velocity a The continues forward at of 6.0 m/s, the ball velocity of the m/s. What was the original a. ball? 4.0 m/s b, 5,7 m/s c, 6.6 m/s d. 3.3 m/s 1. A ball is rolled horizontally off a table with initial speed of 0.24 m/s. watch measures the ball's trajectory time from table to the floor to be 0.30 s. How far away from the table does the ball land? (g 9.8 m/s and air resistance is negligible) a. 0.055 m b. 0,072 m c. 1.2 m 1.9 m 12. Hooke's law spring is compressed 12.0 cm from equilibrium and the potential energy stored is 72.0 J. What is the spring constant in this case? a. 10 000 N/m b, 5 000 N/m c, 1 200 N/m d. No answer is correct. 13. A 0.12-kg ball is moving at 6 m/s when it is hit by a bat, causing it to reverse direction and have a of of 14 m/s. What is the change in the magnitude the momentum of the ball? a. 0.39 kg m/s b, 0.42 kg m/s c, 1.3 kg ms d 24 kg ms 120 m west, moves m cast, then moves 90 m. If moves east again distance of is the direction, what ats as resultant displacement? som somExplanation / Answer
10. Applying momentum conservation for collision,
( 7 v) + (2 x 0) = (2 x 6) + (7 x 4)
v = 5.7 m/s
Ans(b)
11. d = 0.24 x 030 = 0.072 m (there is no force(acceleration) in horizontal direction hence distance = speed x time )
Ans(b)
12. PE = k x^2 / 2
x = 12 cm = 0.12 m
72 = k (0.12^2) / 2
k = 10 000 N/m
Ans(A)
13. vi = 6 m/s
vf = - 14 m/s
change in momentum = m (vf - vi)
= 0.12 ( -14 - (6)) = - 2.4
magnitude = 2.4 kg m/s
Ans(d)
14. r = 70 + (-120) + 90 = 40 m
Ans(A)
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