At one instant, force Upper F Overscript right-arrow EndScripts equals 1.57 j Ov
ID: 1567664 • Letter: A
Question
At one instant, force Upper F Overscript right-arrow EndScripts equals 1.57 j Overscript EndScripts N acts on a 0.517 kg object that has position vector r Overscript right-arrow EndScripts equals left-parenthesis 8.00 i Overscript EndScripts minus 8.00 k Overscript EndScripts right-parenthesis m and velocity vector v Overscript right-arrow EndScripts equals left-parenthesis negative 9.58 i Overscript EndScripts plus 9.58 k Overscript EndScripts right-parenthesis m divided by s. About the origin and in unit-vector notation, what are (a) the object's angular momentum and (b) the torque acting on the object?
Explanation / Answer
given
F = 1.57 j
m = 0.517 kg
r = 8 i - 8k
v = -9.58 i + 9.58 k
a) angular momentum, L = m*(r cross v)
= 0.517*((8i - 8k) cross (-9.58i + 9.58k))
= 0.517*(8*9.58(-j) + 8*9.58*(j) )
= (0i + 0j + 0k) kg.m^2/s
b) Torque, T = r cross F
= ((8i - 8k) cross 1.57 j )
= 8*1.57 k - 8*1.57*(-i)
= 12.6 i - 12.6 k
= (12.6 i + 0 j - 12.6 k ) N.m
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