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The digital sign outside a local bank reports that the temperature is 41 degree

ID: 1565941 • Letter: T

Question

The digital sign outside a local bank reports that the temperature is 41 degree C. What is the temperature in degrees Fahrenheit? A) 79 degree F B) 99 degree F C) 106 degree F D) 111 degree F E) 120 degree F Three thermometers are in the same water bath. After thermal equilibrium is established, in is found that the Celsius thermometer reads 0 degree C, the Fahrenheit thermometer reads 12 degree F, and the Kelvin thermometer reads 273 K. Which one of the following statements is the most reasonable conclusion? A) The Kelvin thermometer is incorrect. B) The Celsius thermometer is incorrect. C) The Fahrenheit thermometer is incorrect. D) All three thermometers are incorrect. E) The three thermometers are at different temperatures. Three thermometers are placed in a closed, insulated box and are allowed to reach thermal equilibrium. One is calibrated in Fahrenheit degrees, one in Celsius degrees, and one in Kelvins. The Celsius thermometer reads -40 degree C and the Kelvin thermometer reads 233 K. Which one of the following statements is necessarily true? A) The Kelvin thermometer should read -233 K. B) The Kelvin thermometer should read -313 K. C) The Fahrenheit thermometer must read -40 degree F. D) If water were found within the box, it must be in the liquid state. E) If the temperature of the contents is increased by 10 degree C, the reading on the Kelvin thermometer should increase by 273 K. Oxygen boils at -183 degree C. This temperature is A. -275 degree F B. -297 degree F. C. -329 degree F. D. -361 degree F. The specific heat of water is 4.2 kJ/kg. degree C. When 400 of heat is added to 12 kg of water at 2 degree C, its final temperature is A. 5.9 degree C. B. 79 degree C.

Explanation / Answer

43)

0 degree = 32 Fahrenheit

T(f) = (41 x 9/5) + 32

T(f) = 105.8 F = 106 F (approx)

44)

Ans (a) kelvin thermometer is incorrect..

Because 0 degree C = 273 K

45)

Ans (c) the fahrenheit temperature must read 40 F

T(f) = 9/5(-40) + 32 = -72 + 32 = -40 F

46)

T(f) = (-183 x 9/5) + 32

T(f) = -297.4 F = -297 F

Ans(b) -297 F

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