The two wires shown in the figure below are separated by d = 7.8 cm and carry cu

Question

The two wires shown in the figure below are separated by d = 7.8 cm and carry currents of I = 4.80 A in opposite directions. (a) Find the magnitude and direction of the net magnetic field at a point midway between the wires. 4.92e-5 (b) Find the magnitude and direction of the net magnetic field at point P_1, 7.8 cm to the right of the wire on the right. magnitude mu T direction (c) Find the magnitude and direction of the net magnetic field at point P_2, 2d = 15.6 cm to the left of the wire on the left. magnitude mu T direction

Explanation / Answer

here,

d = 0.078 m

I = 4.8 A

a)

the magnetic feild at the midpoint between them , B = u * I /( 2 * pi*d/2 ) + u * I /( 2 * pi*d/2 )

B = 2 * 1.26 * 10^-6 * 4.8 /(pi * 0.078 )

B = 49.4 * 10^-6 T = 49.4 uT

b)

the magnetic feild at the P1 , B1 = u * I /( 2 * pi * d) - u * I /( 2 * pi* 2 * d )

B1 = 2 * 1.26 * 10^-6 * 4.8 /(pi * 0.078 ) * ( 1/2 - 1/4)

B1 = 12.35 * 10^-6 T = 12.4 uT

c)

the magnetic feild at P2 , B2 = u * I /( 2 * pi * 2 * d ) - u * I /( 2 * pi* 3 * d )

B2 = 2 * 1.26 * 10^-6 * 4.8 /(pi * 0.078 ) * ( 1/4 - 1/6)

B2 = 4.12 * 10^-6 T = 4.12 uT

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