A 1.0-m long wire is carrying amount current. The wire is placed perpendicular t

Question

A 1.0-m long wire is carrying amount current. The wire is placed perpendicular to a magnetic field of strength 0.20 T. If the wire experiences a force of 0.60 N, what is the current moving through the wire? A) 4.0 A B) 5.0 A C) 2.0 A D) 1.0 A It takes 10 J of energy to move 2.0 C of charge from point A to point B. What is the potential difference between points A and B? A) 20. V B) 5.0 V C) 0.50 V D) 0.20 V E) zero A typical public utility (power company) supplies electricity at an approximate cost of A) $1/kW middot h. B) $100/kW middot h. C) 1/kW middot h. D) 510/kW middot h. E) 10/kW middot h. The force of attraction between a -30.0 mu C and +94.0 mu C charge is 4.00N. What is the separation between these two charges? A) 2.52m B) 2.49 m C) 2.10 m D) 1.13 m E) 3.67 m A parallel-plate capacitor has plates of area 0.20 m^2 separated by a distance of 1.0 mm. What is this capacitor's capacitance? A) 4.2 time 10^-10 F B) 40 F C) 1.8 times 10^-9 F D) 3.5 times 10^-10 F E) 200 F A piece of plastic has a net charge of +2.00 mu C. How many more protons than electrons does this plastic have? A) 1.25 times 10^13 B) 1.25 times 10^19 C) 0 D) 2.50 times 10^13 E) 2.50 times 10^19 A charge of 12 C passes through an electroplating apparatus in 2.0 min. What is the average current? A) 6.0 A B) 0.24 A C) 0.60 A D) 1.0 A E) 0.10 A Light of wavelength lambda = 480 nm passes through a pair of slits with separation 2.2 times 10^-5 m. What is the angle corresponding to the second bright fringe? A) 2.5 degree B) 1.5 degree C) 5.0 degree D) 4.3 degree E) 3.7 degree

Explanation / Answer

18. (D)

19. F = i L B

0.60 = i x 1 x 0.20

i = 3 A

Ans(E)

20 . U = q deltaV

10 = 2 C deltaV

delaV = 5 V

Ans(B)

21. Ans(E)

22. F = k q1 q2 / r^2

4 = (9x 10^9) (30 x 10^-6)(94 x 10^-6) / r^2

r = 2.52 m

Ans(A)

23. C = e0 A / d

C = 1.8 x 10^-9 F

Ans(C)

24. n = 2 x 10^-6 / (1.6x 10^-19) = 1.25 x 10^13

Ans(A)

25. I = Q / t = 12 / (2 x 60s) = 0.10 A

Ans(E)

6. sin(theta) = 2 x 480 x 10^-9 / (2.2 x 10^-5)

theta = 2.5 deg

Ans(A)

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