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my SMU x Canvas x Files x M WileyPLl x e secure https://edugen wileyplus.com/edugen/student/mainfr uni Apps O (The Java e Complete Printf for Ja Gls used 2007 Lexus ES s D New Tab Formatting Wiley PLUS: My Wiley PLUS I Help I Contact Us I Log Halliday, Fundamentals of Physics, 10e Introductory Physics (PHYs 1303, 1304, 1307, 130 Gradebook ORION PRINTER VERSION BACK Chapter 34, Problem 106 In the figure, an object is placed in front of a converging lens at a distance equal to twice the focal length fi of the lens. On the other side of the lens is a concave mirror of focal length separated from the lens by a distance 2(fi f2). Light from the object passes rightward through the lens, reflects from the mirror, passes leftward through the lens, and forms a final image of the object. Take f 6.6 cm and f2 6.9 cm. What are (a) the distance between the lens and the final image and (b) the overall lateral magnification M of the ou ect? Is the image (c) real or virtual (if it is virtual, it requires someone looking through the lens toward the mirror (d) to the left or right of the lens, and (e) inverted or noninverted relative to the object? Units (a) Number (b) Number Units (e) click if you would like to show work for this questi Open Show Work olicy l 2000-2017 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley &Sons;, Inc.

Explanation / Answer

here,

for the lens ,

f1 = 6.6 cm

the object distancve , do1 = 2 * f1 = 13.2 cm

let the image distance be di1

using the lens formula

1/fi1=1/do1+ 1/di1

1/6.6 = 1/13.2 + 1/di

di1 = 13.2 cm

for the mirror

f2 = 6.9 cm

do2 = 13.8 cm

let the image distance be di2

1/f2 = 1/di2 + 1/do2

1/6.9 = 1/di2 + 1/13.8

di2 = 13.8 cm

a)

the final image is 13.2 cm from the lens

b)

the overall lateral magnification , m = (-di1 /do1) *(-di2/do2)

m = (- 13.2 /13.2) * ( -13.8/13.8)

m = 1

c)

the image formed is real

d)

the image is formed to the right of lens

e)

the image is non inverted

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