A pot on the stove contains 600 g of water at 20°C. An unknown mass of ice that

Question

A pot on the stove contains 600 g of water at 20°C. An unknown mass of ice that is originally at 10°C is placed in an identical pot on the stove. Heat is then added to the two samples of water at precisely the same constant rate. Assume that this heat is transferred immediately to the ice or water (in other words, neglect the increase in temperature for the pot). We will also neglect evaporation. The ice melts and becomes water, and you observe that both samples of water reach 50.0°C at the same time.

Explanation / Answer

heat absorbed by water = heat absorbed by ice

Mwater*Swater*dt1 = Mice*(Sice*dt2 + Lf + Swater*dt2)

0.6*4186*(50-20) = Mice*((2060*10) + 3.35*10^5 + (4186*50))

Mice = 0.133 kg = 133 grams <<<<<------answer

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