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Water stands at a depth H in a large open tank whose side walls are vertical (Fi

ID: 1560727 • Letter: W

Question

Water stands at a depth H in a large open tank whose side walls are vertical (Figure 1).A hole is made in one of the walls at a depth h below the water surface. At what distance R from the foot of the wall does the emerging stream strike the floor? Express your answer in terms of the given quantities. How far above the bottom of the tank could a second hole be cut so that the stream emerging from it could have the same range as for the first hole? Express your answer in terms of the given quantities.

Explanation / Answer

  A). R = velocity of efflux of water*time of fall
velocity of efflux of water = sqrt(2gh)
Time of fall of water (from s = ut +1/2 at^2 in vertical direction))
= sqrt[2g(H - h)/g]
Therefore,
R = sqrt(2gh)*sqrt[2g(H - h)/g]
= sqrt[4(H-h)h]
B. It is at height h from the bottom.