m Secure l https://session a ssignmentProblemID 73556ss4 College Physics 2 PHY 2

Question

m Secure l https://session a ssignmentProblemID 73556ss4 College Physics 2 PHY 2054-003 (2173) Ch 23 HW Pad 2) Problem 23.90 A small object is 25.0 cm from a diverging lens as shown in the figure( 1 A converging lens with a focal length of 11.9 cm is 30.0 the right of the Part A diverging lens. The two-lens system forms a real inverted image 17.0 cm to the right of the converging What is the focal length of the diverging lens? Figure 1 of 1 f- 19.0 Submit M Answers Give Up incorrect; Try Again: 3 attempts remaining 30.0 cm 17.0 cm 25.0 cm previous l 18 of 27 next Continue

Explanation / Answer

Diverging lens will produce a virtual image

1/f = 1/u - 1/v

1/25 - 1/v = 1/f

converging lens, 1/(30 + v) + 1/17 = 1/11.9

(30 + v) = 1 / 0.0252

v = 9.667 cm

substitute in above equation

1/f = 1/25 - 1/9.667

Diverging lens focal length f = -15.76 cm

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