A light ray of wavelength 589 nm trailing through air is incident on a smooth, f

Question

A light ray of wavelength 589 nm trailing through air is incident on a smooth, flat slab glass at an angle of 30 degree to the normal. The index of refraction is 1.52. Find the angle of refraction. a) 19.2 degree b) 10.0 degree c) 15.2 degree d) 25 degree e) None Light of wavelength 589 nm in a vacuum passes through a glass of index of refraction of 1.458. [For questions: 2, 3, and 4] Calculate the speed of light in the glass. a) 2.06 times 10^4 m/s b) 2.60 times 10^6 m/s c) 4.06 times 10^6 m/s d) 3.60 times 10^3 m/s e) None Calculate the wavelength of this light in the glass. a) 404 nm b) 604 nm c) 444 nm d) 350 nm e) None Calculate the frequency of this light in the glass. ?) 5.09 times 10^14 J b) 7.09 times 10^14 J c) 6.66 times 10^14Hz d) 5.09 times 10^14 Hz e) None An object is placed 16.0 cm away from a concave mirror. An image location is 8.0 cm. Find the focal length. a) 5.33 m b) -5.33 cm c) 5.33 cm d) 4.22 cm e) None An object is placed 16.0 cm away from a convex mirror with focal length 8.0 cm. find the location of the image. a) 5.33 m b) -5.33 mm c) -5.33 cm d) 4.22 cm e) None A screen is separated from a double-slit source by 1.20 m. The distance between the two slits is 0.030 mm. The second-order bright fringe is measured to be 4.50 cm from the center line. Determine the wavelength of the light. a) 563 nm b) 563 cm c) 563 pm d) 563 m e) None A monochromatic light from a helium-neon laser with wave length 632.8 nm is incident on a diffraction grating containing 6.00 times 10^3 line/cm. [For questions 8, and 9] Find the split spacing (d). a) 1.67 times 10^-3 m b) 1.67 times 10^-4 cm c) 1.67 times 10^-4 mm d) 1.67 times 10^-3 cm e) None Find the angle for the first-order maximum. a) 22.3 degree b) 42.3 degree c) 12.3 degree d) 32.3 degree e) None

Explanation / Answer

(1)

from snell's law of refraction

n1*sini = n2*sinr

1*sin30 = 1.52*sinr

angle of refraction r 19.2 degrees

OPTION (a)

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(2)

speed of light in medium v = c/n

v = 3*10^8/1.458 = 2.06*10^8 m/s

OPTION (a)

===============

3)

wavelength in medium = wavelength in air/n

wavelength in medium = 589/1.458 = 404 nm <<<-----answer

OPTION (a)

========================

(4)

frequency f = c/wavelength in air

f = 3*10^8/(589*10^-9) = 5.09*10^14 Hz <<<---answer

===================

5)

1/s + 1/s' = 1/f

1/16 + 1/8 = 1/f

f= 5.33 cm <<<------answer

=============

(6)

1/s + 1/s' = 1/f

1/16 + 1/s' = -

s' = -5.33 cm <<<------answer

============

7)

y = m*lambda*R/d

for m = 2

4.5*10^-2 = 2*lambda*1.2/(0.03*10^-3)

lambda = 563 nm <<<<<<------answer

=================

(8)

d = 1 cm/6000 = 0.01/6000 = 1.67*10^-6 m = 1.67*10^-4 cm <<<------answer

OPTION (b)

=============

9)

In diffraction

d*sintheta = m*lambda

m = 1

1.67*10^-6*sintheta = 1*632.8*10^-9

theta = 22.3 <<<< =======answer

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