ten VA P1520 Nuclear Physics x CG energy and wavelength x C Secure h ps://www.we
ID: 1557723 • Letter: T
Question
ten VA P1520 Nuclear Physics x CG energy and wavelength x C Secure h ps://www.webassign.net/ 5308775 web/Student/Assignment-Responses/submit?dep 8. -1 points KnightCPMA3 30.P009. My Notes A 12 c' nucleus has an excitation energy of 5.00 Mev and decays to the ground state by emitting a gamma ray. Determine the frequency (in s of the emitted radiation. Submit Answer Save Progress Practice Another Version -12 points knightCPMA3 30.P010 My Notes The radioisotope TC is an isotope that is sometimes given to patients because it emits gamma rays and has a relatively short ha e of 6.05 h. Because it emits gamma rays, To can be used as a tracer when performing imaging on a specific part of the human body. (a) nd the decay constant of To (in h-1). (b) Find the number of Tc nuclei needed to provide a activity of 1.78 Hci. n 10. O -1 points KnightCPMA3 30.P007. My Notes Consider the following nuclear reaction Ac- Fr He and determine the Q value or total energy released (in Mev) in this process. (Let the atomic mass of Ac be 225.0232 u, the atomic mass of 87 Fr be 221.0143 u and the atomic mass of He be 4.0015 u) MeV 9:31 PM A 4 Ask me anything 4/11/2017 RAExplanation / Answer
8) Energy of emited photon, E = 5 MeV
= 5*10^6*1.6*10^-19
= 8*10^-13 J
now use, E = h*f
==> f = E/h
= 8*10^-13/(6.626*10^-34)
= 1.21*10^21 s^-1
9)
a) decay constant, lamda = 0.693/half life time
= 0.693/6.05
= 0.114 hour^-1
b) we know, 1 Ci = 3.7*10^10 desentegrations/second
and lamda = 0.114 h^-1
= 0.114/(60*60) s^-1
= 3.17*10^-5 s^-1
Activity, A = lamda*N
==> N = A/lamda
= 1.78*3.7*10^10/(3.17*10^-5)
= 2.08*10^15 nuclie
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.