3) The small piston of a hydraulic lift has a cross-sectional area of 3.00 cm2,

Question

3) The small piston of a hydraulic lift has a cross-sectional area of 3.00 cm2, and its large piston has a cross-sectional area of 200 cm2 as shown below. What downward force of magnitude F1 must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN? Ans: 225N


3) The small piston of a hydraulic lift has a cross-sectional area of 3.00 cm2, and its large piston has a cross-sectional area of 200 cm2 as shown below. What downward force of magnitude F1 must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN? Ans: 225N


3) The small piston of a hydraulic lift has a cross-sectional area of 3.00 cm2, and its large piston has a cross-sectional area of 200 cm2 as shown below. What downward force of magnitude F1 must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN? Ans: 225N

Explanation / Answer

the pressure difference at the two ends is same

dP1 = dP2

F1*A1 = F2*A2

F1 = applied force

A1 = area of cross section at small end = 3 cm^2 = 3*10^-4 m^2

A2 = area of cross section at large end = 200 cm^2 = 200*10^-4 m^2

F2 = weight Fg = 15*10^3 N

F1*3*10^-4 = 15*10^3*200*10^-4

F1 = 1000 KN

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