Question 13 of 15 a Sapling Learning macmillan learning A 5.55-mm-high firefly s

Question

Question 13 of 15 a Sapling Learning macmillan learning A 5.55-mm-high firefly sits on the axis of, and 13.5 cm in front of, the thin lens A, whose focal length is 6.95 cm. Behind lens A there is another thin lens, lens B, with focal length 29.1 cm. The two lenses share a common axis and are 62.1 cm apart. Is the image of the firefly that lens B forms real orvirtual? Virtual O Real How far from lens B is this image located (expressed as a positive number)? Number cm What is the height of this image (as a positive number)? Number Is this image upright or inverted with respect to the firefly? O Upright O Inverted Map

Explanation / Answer

let's assume that both the lenses are converging

Image ffor first lens

1/f = 1/v + 1/u

1/6.95 = 1/ v + 1/13.5

1/v= 1/6.95- 1/13.5 = ( 13.5- 6.95)/( 13.5 x 6.95 )

v= 93. 825/ 6.55= 14.324 cm apprx ( on the right side of the first lens)

object distance for second lens= 62.1- 14.324 = 47.77 cm apprx

1/29.1= 1/v + 1/47.77

1/v= ( 47.77 -29.1)/ ( 47.77 x 29.1)

v =1390.107/ ( 18.67) = 74.456 cm apprx

a) Image is real

b)74. 456 cm

c) m = ( 14.324)/ (13.5 ) ( 74.456/ 47.77) = 1.65

image height = 9.178 mm apprx

d)inverted

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