Okay, so I know the answer to the question is B. I\'m not sure how to arrive at

Question

Okay, so I know the answer to the question is B. I'm not sure how to arrive at the solution tho. Could someone walk write out the work so I can see how its done?

Problem 1. This figure shows two small objects each of mass m connected by a low-mass rod of length L. At a particular instant they have the velocities shown in the accompanying diagram. We are looking down on the system which is sliding past the A icy surface, the plane. z (out of page) What is the translational kinetic energy of the system and is it less than, equal to or greater than the system's total kinetic energy? A. K B. K D. K E. K

Explanation / Answer

Ktrans=0.5*2m*vcm2

2mvcm=mv1+mv2

vcm=(v1+v2)/2

Ktrans=0.5*2m*((v1+v2)/2)2

Ktrans=(1/4)m(v1+v2)2

there must be a rotational energy of rod

Ktrans+Krotational=Ktotal

so Ktrans=(1/4)m(v1+v2)2<Ktotal

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