A group of students, performing the same \"Uniform Circular Motion\" experiment

Question

A group of students, performing the same "Uniform Circular Motion" experiment that you performed in lab, obtained the following results. For this table, r is the distance from the center of rotation to the radius indicator (i.e, the post that marks the position of the center of the bob during rotation), m_h is the total hanging mass (including the hanger), and rotations. (a) Use Excel to construct a spreadsheet the show the following. (you will not submit this spreadsheet However, the results will be needed later in this problem.) (i) the above data (ii) all calculations needed to compute the acceleration, a, for each trial (ii) a graph of m_hg vs a_c (iv) Use the trendline option to draw the best fit line and determine its slope. (b) Report this value below. The average NASCAR race car weighs 3400 b. At a recent NASCAR race the cars went flying around the banked curves at a raceway. The banking of the turns at the raceway are theta = 28 degree. The horizontal component of the normal force supplies the needed centripetal force in this case (not the fiction force). (a) What is the algebraic expression for the component of the normal force in the vertical direction? (Use the following as necessary: f_N and theta .) f_N, y = F_N cos(theta) (B) What is the algebraic expression for the gravitational force on the car in terms of its mass? F_g = mg (c) What is the algebraic expression for the component of the normal force in the horizontal direction? (Use the following as necessary: F_N and theta .) F_N, X = F_N sin (theta) (d) Use your answer to parts (a), (b), and (c) to eliminate F_N and write an expression for the centripetal force on the car in terms of the mass m of the car and the angle theta. F_c = mg tan(theta) (e) If the car is gong around the curve at a speed of 160 mph calculate the centripetal force acting on the car. (f) Suppose the curve was not banked. For the same radius, what centripetal force will be needed to keep the car going around the curve at the same speed of 160 mph?

Explanation / Answer

As you have already solved from part a) to part d) so we need to solve for part e) and part f).

Part e ) f(c) = 1542.2 kg * 9.8 * tan ( 28 ) = 8036.074506 Newton ===========ANSWER)

Part f) answer remains same F(c) = 8036.074506 Newton ================ANSWER)

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