A crate rests on a horizontal frictionless surface pulled with a force of 40.0 N

Question

A crate rests on a horizontal frictionless surface pulled with a force of 40.0 N at an angle 30.0 degree through a distance of 1.50 m, its speed r by the pulling force? (b) What is When you take your 1200-kg car out for a spin, you go around a corner of radius 48 m with a speed of 16 m/s. The coefficient of static friction between the car and the road is 0.88. Assuming your car does not skid, (a) what is the force exerted on it by static friction? (b) what is the maximum speed your car can maintain without skidding?

Explanation / Answer

f = mue*n

n = mg

f = mue*mg

f = 0.88*1200*9.8 = 10348.8 N

f = mv^2/r

v = sqrt(mue*rg) = 20.35 m/s

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