#19 #26 #28 Help... Please show your work so that I can follow and know how to d
ID: 1554165 • Letter: #
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#19 #26 #28 Help... Please show your work so that I can follow and know how to do on my own with similar problems. Thanks a Bunch!
(b) Number 2 Units (c) Number 3 Units significant digits a disabled; the tolerance is +/-2% significant digits are disabled, the tolerance is +/-2% significant digits are disabled the tolerance is +/-2% Chapter 14, Problem 019 A large aquarium of height 6 m is filled with fresh water to a depth of D 2.40 m. one wall of the aquarium consists of thick plastic with w how much does the total force on that wall increase if the aquarium is next filled to a depth of D 4.40 m? (Note: use g 9.81 m/s and p 998 kg/m3.) 1 Units Number Significant digits are disabled; the tolerance is +/-2% Chapter 14, Problem 026 To of density 1050 up a straw to a maximum height of 3.18 cm, what minimum gauge pressure (in atmospheres) must you produce your lungs? Number Units Significant digits are disabled, the tolerance is +/-2% Chapter 14, Problem 028 A piston of cross-sectional area a is used in a hydraulic press to exert a force of magnitude f on the enclosed liquid. A small figure). If the piston connecting leads to a larger piston of cross-sectional area piston will balance a diameters are 2.89 cm and 65.5 cm, what force magnitude on the small 13.6 kN force on the large piston? 1 Units Number Significant digits are disabled; the tolerance is +/-2%Explanation / Answer
(19) We know that the horizontal force will be
F = pgAX
where p is the density of the water , g is the acceleration due to gravity
A is the area and X is the centre of gravity
Area (A) = Depth*width
So change in force = Final force - Initial force
= pg(A2X2 - AX )
Final area = final depth*width = 4.4*7.7 = 33.88
Initial area = Initial depth*width = 2.4*7.7 = 18.48
Now, Initial centre of gravity = depth/2 = 2.4/2 = 1.2
Final centre of gravity = final depth / 2 = 4.4/2 = 2.2
Change in force = pg(33.88*2.2 - 18.48*1.2) = 51.262*104 N
By this amount force on wall will increase
(26)
We know for sucking we have to create vaccum
therefore
pressure = - pgh = 1050*9.81*3.18*10-2 = -327.56 Pa
minus sign indicates that the pressure is below atmospheric or vaccum .
(28)
From the pascal law , we know that the pressure will remain same at all points, therefore
P1 = P2
where 1 and 2 indicates small and large area
F1 /a = F2/A
F1 = F2(a/A) = 13.6*(a/A)
we know that area = (Pi/4)d2
therefore a/A = (d1/d2)2
F1 = F2(a/A) = 13.6*(2.89 /65.5)2 = 0.0265 kN
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