A sample of rock is found to contain 2.5 times as many lead-207 nuclei as uraniu
ID: 1553905 • Letter: A
Question
A sample of rock is found to contain 2.5 times as many lead-207 nuclei as uranium-235 nuclei. What is the fraction of uranium-235 that now remains (relative to the original number of uranium-235 that was in the sample)? Express your answer using two significant figures. Fraction remaining = ____ On the basis of the data given in More Precisely 7-2, what is the age of the sample (Be careful not to round your answer from the previous part). Express your answer using two significant figures. t = ____ On the basis of the data given in More Precisely 7-2, and the age you calculated In part B, what ratio of uranium-238 to lead-206 nuclei would you expect in this same sample? Express your answer using two significant figures.Explanation / Answer
no of Uranium molecules present in the sample = x
no of Lead molecules present in the sample = 2.5*x
total no of molecules in the sample = x + 2.5*x
= 3.5*x
the fraction of uranium that now remains = no of uranium molecules present/total no of molecules
= x/(3.5*x)
= 0.286
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