fox File Edit View History Bookmarks Tools Window Help 100% Sun 10:14 PM Jo 4) M
ID: 1553697 • Letter: F
Question
fox File Edit View History Bookmarks Tools Window Help 100% Sun 10:14 PM Jo 4) MasteringPhysics Exam 2 a offset next&assignmentProblemlDa7693;' e a, search HYS 1402-94L. 2 Problem 23.3 previous l 6 of 10 Problem 23.3 Part A If the magnetic nux through this surface has a magnitude of 5.3'10 T.m2 what is the strength of the A magnetic field is oriented at an angle of 45 to the normal of a rectangular area 5.8 cm by 7.1 cm magnetic Express your answer using two significant figures. My Answers give Up Eeedback ContinueExplanation / Answer
theta=45degrees
area=5.8x7.1cm2
=41.18m2
magnetic flux=BAcos45
B=magnetic flux/(Acos45)
=(5.3x10-5)/(41.18x10-4xcos45)
=18.2mT
the strength of the magnetic field is
B=18.2mT
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.