A tennis player swings her 1000 g racket with a speed of 12 m/s. She hits a 60 g

Question

A tennis player swings her 1000 g racket with a speed of 12 m/s. She hits a 60 g tennis ball that was approaching her at a speed of 22 m/s. The ball rebounds at 40 m/s.

(a) How fast is her racket moving immediately after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision.

Answer: 8.28 m/s

(b) If the tennis ball and racket are in contact for 10 ms, what is the average force that the racket exerts on the ball?

Answer: 372 N

(c) How does this compare to the ball's weight?

Favg/Wball = __?__

I got the answers for Parts A & B, but I can't figure out C. I tried dividing 372 N by 0.06 kg (weight of the tennis ball) but my answer was wrong

Explanation / Answer

According to the given problem,

Ya! you mistake is weight if the ball is = mg

i.e W = 0.06*9.8 = 0.588

C) Now, the rationis ,

Favg/Wball = 372/0.588 = 632.65

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.