1) ) move at 1.7×10 6 m / s . Part A What magnetic field strength would be requi
ID: 1553401 • Letter: 1
Question
1) ) move at 1.7×106 m/s .Part A
What magnetic field strength would be required to bend them into a circular path of radius r = 0.13 m ? Express your answer using two significant figures. B = T2) Part A What is the magnitude of the force per meter of length on a straight wire carrying an 9.20-A current when perpendicular to a 0.60-T uniform magnetic field? Express your answer to two significant figures and include the appropriate units. F/l = ........(units) ..........(value)
Part B What if the angle between the wire and field is 45.0 ? Express your answer to two significant figures and include the appropriate units. F/l =
1) ) move at 1.7×106 m/s .
Part A
What magnetic field strength would be required to bend them into a circular path of radius r = 0.13 m ? Express your answer using two significant figures. B = T2) Part A What is the magnitude of the force per meter of length on a straight wire carrying an 9.20-A current when perpendicular to a 0.60-T uniform magnetic field? Express your answer to two significant figures and include the appropriate units. F/l = ........(units) ..........(value)
Part B What if the angle between the wire and field is 45.0 ? Express your answer to two significant figures and include the appropriate units. F/l =
m/s . m/s . m/s .
Part A
What magnetic field strength would be required to bend them into a circular path of radius r = 0.13 m ? Express your answer using two significant figures. B = T2) Part A What is the magnitude of the force per meter of length on a straight wire carrying an 9.20-A current when perpendicular to a 0.60-T uniform magnetic field? Express your answer to two significant figures and include the appropriate units. F/l = ........(units) ..........(value)
Part B What if the angle between the wire and field is 45.0 ? Express your answer to two significant figures and include the appropriate units. F/l =
Part A
What magnetic field strength would be required to bend them into a circular path of radius r = 0.13 m ? Express your answer using two significant figures. B = T2) Part A What is the magnitude of the force per meter of length on a straight wire carrying an 9.20-A current when perpendicular to a 0.60-T uniform magnetic field? Express your answer to two significant figures and include the appropriate units. F/l = ........(units) ..........(value)
Part B What if the angle between the wire and field is 45.0 ? Express your answer to two significant figures and include the appropriate units. F/l =
Part A
What magnetic field strength would be required to bend them into a circular path of radius r = 0.13 m ? Express your answer using two significant figures. B = T2) Part A What is the magnitude of the force per meter of length on a straight wire carrying an 9.20-A current when perpendicular to a 0.60-T uniform magnetic field? Express your answer to two significant figures and include the appropriate units. F/l = ........(units) ..........(value)
Part B What if the angle between the wire and field is 45.0 ? Express your answer to two significant figures and include the appropriate units. F/l =
B = T
2) Part A What is the magnitude of the force per meter of length on a straight wire carrying an 9.20-A current when perpendicular to a 0.60-T uniform magnetic field? Express your answer to two significant figures and include the appropriate units. F/l = ........(units) ..........(value)
Part B What if the angle between the wire and field is 45.0 ? Express your answer to two significant figures and include the appropriate units. F/l =
B = T
2) Part A What is the magnitude of the force per meter of length on a straight wire carrying an 9.20-A current when perpendicular to a 0.60-T uniform magnetic field? Express your answer to two significant figures and include the appropriate units. F/l = ........(units) ..........(value)
Part B What if the angle between the wire and field is 45.0 ? Express your answer to two significant figures and include the appropriate units. F/l =
B = T
Explanation / Answer
1)qvB = mv^2/r
=>B = mv^2/qvr = mv/qr
=>B = [{6.6 x 10^-27 x 1.7 x 10^6}/{2 x 1.6 x 10^-19 x 0.13}]
=>B = 0.27 Tesla
2)
Magnetic force per unit length = B*I*sin(theta)
Part A:
When perpendicular, force per unit length = B*I*sin(90) = B*I = 0.6T*9.20A = 5.52 N/m
Part B:
At 45 deg, force per unit length = B*I*sin(45) = 0.6T*9.20A*0.707 = 3.9 N/m
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