(a) A luggage carousel at an airport has the form of a section of a large cone,

Question

(a) A luggage carousel at an airport has the form of a section of a large cone, steadily rotating about its vertical axis. Its metallic surface slopes downward toward the outside, making an angle of 16.0° with the horizontal. A piece of luggage having mass 30.0 kg is placed on the carousel at a position 7.46 m measured horizontally from the axis of rotation. The travel bag goes around once in 42.0 s. Calculate the force of static friction exerted by the carousel on the bag.

(b) The drive motor is shifted to turn the carousel at a higher constant rate of rotation, and the piece of luggage is bumped to another position, 7.94 m from the axis of rotation. Now going around once in every 32.7 s, the bag is on the verge of slipping down the sloped surface. Calculate the coefficient of static friction between the bag and the carousel.

Explanation / Answer

(a)

Speed of bag,

v = 2*pi*r / t = 2*3.14*7.46 / 42

v = 1.115 m/s

cetripetel force,

Fc = m*v^2 / r = 30*(1.115)^2 / 7.46

Fc = 5 N

Net force in x direction is,

Fr*cos16 - N*sin16 = 5

N = Fr*cos16 - 5 / sin16 ....eq(1)

Forces in y direction,

Fr*sin16 + N*cos16 - 30*9.8 = 0

Put the value of N from eq1,

Fr*sin16 + (Fr*cos16 - 5 / sin16)*cos16 = 294

Fr = 85.54 N

(b)

v = 2*pi*7.94 / 32.7

v = 1.524 m/s

Fc = 30*(1.52)^2 / 7.94

Fc = 8.78 N

Net force in x direction is,

Fr*cos16 - N*sin16 = 8.78

N = Fr*cos16 - 8.78 / sin16 ....eq(1)

Forces in y direction,

Fr*sin16 + N*cos16 - 30*9.8 = 0

Put the value of N from eq1,

Fr*sin16 + (Fr*cos16 - 8.78 / sin16)*cos16 = 294

Fr = 89.48 N

N = 89.48*cos16 - 8.78/sin16 = 280.19 N

We know that,

Fr = u*N

u = 89.48 / 280.19

u = 0.319

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